Question

If a ball is thrown into the air with a velocity of 40 ft/s, it's height in feet t seconds later is given by y=40t - 16t^2. Find the average velocity for the time period beginning when t = 2 and lasting .5 seconds

Answer 1

find \(\frac{f(2.5)-f(2)}{.5}\)

Answer 2

i would use a calculator

Answer 3

is 2.5 and 2 inside of the parenthesis

Answer 4

http://www.wolframalpha.com/input/?i=%2840*2.5+-+16%282.5%29^2-%2840*2-16*2^2%29%29%2F.5

Answer 5

alright thanks! i could read what was inside of them