Question

solve for d when 2x-2yd=y+xd that solved for y i need d

Answer 1

2x-2yd=y+xd

Arrange the variables alphabetically within the expression -2yd. This is the standard way of writing an expression.
2x-2dy=y+xd

Reorder the polynomial 2x-2dy alphabetically from left to right, starting with the highest order term.
-2dy+2x=y+xd

Arrange the variables alphabetically within the expression xd. This is the standard way of writing an expression.
-2dy+2x=y+dx

Reorder the polynomial y+dx alphabetically from left to right, starting with the highest order term.
-2dy+2x=dx+y

Since y contains the variable to solve for, move it to the left-hand side of the equation by subtracting y from both sides.
-2dy+2x-y=dx

Reorder the polynomial -2dy+2x-y alphabetically from left to right, starting with the highest order term.
-2dy-y+2x=dx

Factor out the GCF of -y from the expression -2dy.
-y(2d)-y=dx-2x

Factor out the GCF of -y from the expression -y.
-y(2d)-y(1)=dx-2x

Factor out the GCF of -y from -2dy-y.
-y(2d+1)=dx-2x

Divide each term in the equation by (2d+1).
-(y(2d+1))/(2d+1)=(dx)/(2d+1)-(2x)/(2d+1)

Reduce the expression by canceling out the common factor of (2d+1) from the numerator and denominator.
-(y<X>(2d+1)<x>)/(<X>(2d+1)<x>)=(dx)/(2d+1)-(2x)/(2d+1)

Reduce the expression by canceling out the common factor of (2d+1) from the numerator and denominator.
-y=(dx)/(2d+1)-(2x)/(2d+1)

Combine all similar expressions in the polynomial.
-y=(dx-2x)/(2d+1)

Factor out the GCF of x from the expression dx.
-y=(x(d)-2x)/(2d+1)

Factor out the GCF of x from the expression -2x.
-y=(x(d)+x(-2))/(2d+1)

Factor out the GCF of x from dx-2x.
-y=(x(d-2))/(2d+1)

Multiply each term in the equation by -1.
-y*-1=(x(d-2))/(2d+1)*-1

Multiply -y by -1 to get y.
y=(x(d-2))/(2d+1)*-1

Multiply the rational expressions to get ((x*-1(d-2)))/((2d+1)).
y=(x*-1(d-2))/(2d+1)

Multiply x by -1 to get -x.
y=-(x(d-2))/(2d+1)