Question

8p3 - 1

Answer 1

Are we solving for p?

Answer 2

And do you mean: \[8p ^{3}-1\]

Answer 3

factorise mate.
\[(2p-1)(4p^2+2p+1)\]

Answer 4

factor completely
yes

Answer 5

ah, thank you

Answer 6

@xxxo
\[a^3-1=(a-1)(a^2+a+1)\]

Answer 7

Remember that.