Question

Prove this identity:
csc2 ϴ - cot2 ϴ = sec2 ϴ - tan2 ϴ
PLEASE HELP ME! :D

Answer 1

\[\frac{ 1 }{ \sin^2\theta }-\frac{ \cos^2\theta }{ \sin^2\theta }=\frac{ 1 }{ \cos^2\theta }-\frac{ \sin^2\theta }{ \cos^2\theta }\]
\[LHS=\frac{ 1-\cos^2\theta}{\sin^2\theta }=\frac{ \sin^2\theta }{\sin^2\theta }=1\]
\[RHS=\frac{ 1-\sin^2\theta }{ \cos^2\theta }=\frac{ \cos^2\theta }{ \cos^2\theta }=1\]
RHS=LHS

Answer 2

thanks but i already know the answer po. hehe . :D

Answer 3

yw