Question

Please help!
Use the half-angle identities to express sin 3C in terms of function of 6C.

Answer 1

sin(6C) = 2 sin(3C) cos(3C) ;then by the sin inverse function 6C=sin-1(2s in(3C) cos (3C)

Answer 2

(2s in(3c)? Does that mean 2sin^-1(3c)?

Answer 3

the answer is 6C = sin-1(2 sin(3C) cos(3C) )

Answer 4

It's the inverse of sin, so it's sin^-1, right?

Answer 5

yes its the inverse of sin