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OpenStudy (anonymous):
what u hav to find in this ? dear
OpenStudy (anonymous):
I'm just an elementary child, I don't know how to solve this, can you show me the formula??
OpenStudy (anonymous):
Factor that expression
OpenStudy (anonymous):
got it dear.....what r u saying
OpenStudy (anonymous):
use this formula: sec^2x-cosec^2x=tan^2x-cot^2x
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OpenStudy (anonymous):
so what's the answer?
OpenStudy (anonymous):
a^6 - b^6
= (a³)² - (b³)²
= (a³+b³)(a³-b³)
= (a+b)(a²-ab+b²)(a-b)(a²+ab+b²)
= (a+b)(a-b)(a²+ab+b²)(a²-ab+b²)
here a is sec and b is cosec.............put their values in the last
OpenStudy (anonymous):
did u got what i m trying to tell u ?
OpenStudy (anonymous):
ok, thanks for the help :)
OpenStudy (anonymous):
can i add you in Fb?
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OpenStudy (anonymous):
did u got what i m trying to tell u ......if yes the click the best response if think i hav given u the best response??????/
OpenStudy (anonymous):
yes...
OpenStudy (anonymous):
thx fr awarding me d medal and becoming my fan
OpenStudy (anonymous):
it's my pleasure :)
OpenStudy (anonymous):
r u sending me req................????????
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OpenStudy (anonymous):
in Fb?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
that?
OpenStudy (anonymous):
yes profile pic is mine did u gt that ?
OpenStudy (anonymous):
yes, I sent you request
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