Question

Determine where each of function is continuous.

g(x)= (x-1)/(x^2+1)

Answer 1

I honestly have no idea how to begin.

Answer 2

discontinuty occurs when denominator equals to zero
here if we put denomintor = 0 we get
(x^2+1) = 0
x = i , x= -i where i = iota
thus x become imagnary number when denominator = 0
thus g(x) is continous for all real values of x
therefore g(x) is continous