Question

I had to solve for the variable in: 3(4x-1)-2=17x+10. I got x=-1. How do I check this?

Answer 1

Plug in -1 for x in the equation and see if LHS=RHS

Answer 2

Does that help @Claudilovely?

Answer 3

And that's what I did but it didn't turn out right. . . can you explain? I've been trying to figure this out for the longest.

Answer 4

I do:

3(4(-1)-2=17(-1)+10
3(-5)-2=17(-1)+10
-15-2=17(-1)+10
-15-2=7
17 doesn't epual 7. What did I do wrong?

Answer 5

3(4x-1)-2=17x+10
3*4x-3*1-2=17x+10
12x-3-2=17x+10
12x-5=17x+10
Try solving for x nw nd see vat u get

Answer 6

Where you get the 3 in: 3*4x-3*1-2=17x+10
^
That one

Answer 7

3(4x-1).
this means u have to multiply the terms within the parentheses by 3.
That's what distributive property states.
a(b-c)=a*b-a*c
Getting it?

Answer 8

Oh.... yup!

Answer 9

if u dnt get it plz ask:)

Answer 10

okay

Answer 11

wait. . .but when I got -1 for x, that was right?

Answer 12

nope. -1 is not the solution.
When u plugged it and checke u didnt get LHS=RHS.

Answer 13

nope, i didn't. Then can u explain what x is? So that way, maybe the checking part won't be so annoyingly hard

Answer 14

3(4x-1)-2=17x+10
3*4x-3*1-2=17x+10
12x-3-2=17x+10
12x-5=17x+10
-5=17x-12x+10
-5=5x+10
-5-10=5x
-15=5x
x=-15/5
x=-3
nw plug in -3 and check if LHS=RHS

Answer 15

oh my! That's what I got on my first try, but I thought I was wrong. Wow. . . .

Answer 16

Thank you!!!!!!!!

Answer 17

Welcome:)