Question

Determine where each of function is continuous.

h(x)= (x+1)/(x^2-4x+3)

So I got this so far...

x^2-4x+3
(x-1)(x-3)
x=1 and x=3

So h(x) is continuous everywhere except at x=1 and x=3. Is that right or wrong?

Answer 1

that is correct

Answer 2

put x =1 and x = 3 in denominator and see if you get zero or not
if yes then you are correct else wrong