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Mathematics 14 Online
OpenStudy (anonymous):

Height of a Projectile: The height of an object thrown upward from the roof of a building 408 ft tall, with an initial velocity of 96 ft/sec, is given by the equation h=-16t^2+96t+408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground?

OpenStudy (anonymous):

when it falls on the ground what is the value of h??

OpenStudy (anonymous):

0

OpenStudy (anonymous):

so set that = 0 in the equation

OpenStudy (anonymous):

So it's -16t^2+96t+408=0?

OpenStudy (anonymous):

yes...now solve for t

OpenStudy (anonymous):

Can you show me the steps please?

OpenStudy (anonymous):

-16t^2 + 96t + 408=0 solve the quadratic equation

OpenStudy (anonymous):

Can you show me the steps please?

OpenStudy (mertsj):

\[x=\frac{-96\pm \sqrt{96^2-4(-16)(408)}}{2(-16)}\]

OpenStudy (mertsj):

Simplify that.

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