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Height of a Projectile: The height of an object thrown upward from the roof of a building 408 ft tall, with an initial velocity of 96 ft/sec, is given by the equation h=-16t^2+96t+408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground?
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when it falls on the ground what is the value of h??
0
so set that = 0 in the equation
So it's -16t^2+96t+408=0?
yes...now solve for t
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Can you show me the steps please?
-16t^2 + 96t + 408=0 solve the quadratic equation
Can you show me the steps please?
\[x=\frac{-96\pm \sqrt{96^2-4(-16)(408)}}{2(-16)}\]
Simplify that.
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