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equation in interval [0,2pi) 10. sin 2x + cos x = 0
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Well, sin 2x = 2 sin x . cos x See what to do now?
No? Well this means that sin 2x + cos x = 0 is equivalent to 2.sin x.cos x + cos x = 0 cos x (2sin x + 1) = 0 Now see what to do?
The problem looks for pi something
Intervals such as 0,2pi
If ab = 0, what can you say about a and b? If ab = 0, then a = 0 or b = 0 Likewise if cos x (2sin x + 1) = 0 then cos x = 0 or 2sin x + 1 = 0 Now solve for x, given that x is in the interval [0, 2pi)
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I don't how
Well if cos x = 0, what must x be if x is in [0, 2pi) ?
I don't understand
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