Question

Identify the roots and state the multiplicity

x^6 - 12x^4 + 48x^2 -64 = 0

Answer 1

Thank God! I finally solved it.

x^6 -12x^4+48x^2-64=0
(x^2-4) (x^2-4) (x^2-4)=0
x^2-4=0
x^2=4
x+-2 or x=2 with the multiplicity of 3.

It was extremely hard. Hope I helped.

Answer 2

Oh, before writing (x^2-4(x^2-4) (x^2-4)=0 you should put (x^2-4)^3