OpenStudy (anonymous):

find the sum of the first 6 terms of the geometric sequence for which a^2=0.7 and a^3=0.49

4 years ago
OpenStudy (tkhunny):

$$\dfrac{a^{3}}{a^{2}} = a = \dfrac{0.49}{0.70} = 0.70$$ $$a^{1} = 1$$ Are you SURE you mean $$a^{3}$$, or do you mean $$a_{3}$$?

4 years ago
OpenStudy (anonymous):

I meant to put both of the numbers as subscripts. Sorry?

4 years ago
OpenStudy (tkhunny):

We should know, because it is a geometric sequence, that $$a_{2} * r = a_{3}$$. Use this to solve for the common ratio, r.

4 years ago