Question

find the sum of the first 6 terms of the geometric sequence for which a^2=0.7 and a^3=0.49

Answer 1

\(\dfrac{a^{3}}{a^{2}} = a = \dfrac{0.49}{0.70} = 0.70\)

\(a^{1} = 1\)

Are you SURE you mean \(a^{3}\), or do you mean \(a_{3}\)?

Answer 2

I meant to put both of the numbers as subscripts. Sorry?

Answer 3

We should know, because it is a geometric sequence, that \(a_{2} * r = a_{3}\). Use this to solve for the common ratio, r.