Question

rearrange the equation to isolate A.
H=K+log(A/C)

Answer 1

This is what I've done and I keep getting it wrong. These are the steps the hint provides. Subrtract k, then take the antilog of both sides, and then multiply both sides by C.
\[H-K=\log{\frac{ A }{ C }} \]
\[10^{H-K}=\frac{ A }{C }\]
I get: \[10C ^{H-K}=A\]

Answer 2

Let's pretend that H = 5, and K = 3. Furthermore, C = 5. What is \(C*10^{H-K}\)?

Answer 3

@Dama28 still there?

Answer 4

yeah sorry

Answer 5

So, you've had a little time now, what is the value of \(5*10^{(5-3)} = 5*10^2\) Does that suggest what your mistake was?

Answer 6

so it should be C*10(H-K)=a??

Answer 7

sorry C*10^(H-K)=A

Answer 8

yes!

Answer 9

omg! thank you so much! hahahah I would have never thought of that detail.