Question

rearrange the equation to isolate A.
H=K+log(A/C)

Answer 1

This is what I've done and I keep getting it wrong. These are the steps the hint provides. Subrtract k, then take the antilog of both sides, and then multiply both sides by C.
\[H-K=\log{\frac{ A }{ C }} \]
\[10^{H-K}=\frac{ A }{C }\]
I get: \[10C ^{H-K}=A\]

Answer 2

Let's pretend that H = 5, and K = 3. Furthermore, C = 5. What is \(C*10^{H-K}\)?

Answer 3

@Dama28 still there?

Answer 4

yeah sorry

Answer 5

So, you've had a little time now, what is the value of \(5*10^{(5-3)} = 5*10^2\) Does that suggest what your mistake was?

Answer 6

so it should be C*10(H-K)=a??

Answer 7

sorry C*10^(H-K)=A

Answer 8

yes!

Answer 9

omg! thank you so much! hahahah I would have never thought of that detail.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Read the poem.

Dulce et Decorum Est
by Wilfred Owen

Bent double, like old beggars under sacks,
Knock-kneed, coughing like hags, we cursed through sludge,

Answer 14

Read the excerpt of the poem. Then answer the questions.

excerpt from ''Paul Revere's Ride''
by Henry Wadsworth Longfellow

It was twelve by the village cl

Answer 15

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Answer 16

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Answer 17

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Answer 18

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Answer 19

Just want to check the word order on this assignment

Answer 20

What is the main idea?
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Answer 21

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Answer 22

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Answer 24

triangle congruences

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