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Find the value of x on a right triangle when 2 variables are missing and the hypotenuse is 3 square root of 2
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|dw:1359443877815:dw|for a better look at the problem
|dw:1359444180420:dw| Since BC=AC and <ACB =90 triangle ABC is an isosceles right angled triangle. So <ABC=<BAC=y y+y+90=180 2y+90=180 2y=180-90 2y=90 y=90/2 y=45
|dw:1359444336807:dw| sin45=opp/hyp 1/(sqrt2)=x/(3sqrt2) Can u find x nw? @Suleman_Ahmed
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