OpenStudy (anonymous):

if f(x)=x^(2)+1 and, g(x)=2x, find [f times g](x)

5 years ago
OpenStudy (anonymous):

I think you mean$(f^{o}g)(x)$?This is simply$f(g(x))$If$f(x)=(x)^{2}+1$and$g(x)=2x$just replace every instance of x with 2x.

5 years ago
OpenStudy (anonymous):

yea i think i do mean that.. and why do i do that, just wondering

5 years ago
OpenStudy (anonymous):

$(f^{o}g)(x)=f(g(x))$is where you have f as a function of g, and g is a function of x. So in this particular case$f(g)=(g)^{2}+1$but$g(x)=2x$So replacing g in the first function with its equivalent (2x) gives f(g(x)):$f(g(x))=(2x)^{2}+1$Does that make sense?

5 years ago
OpenStudy (anonymous):

yes it does :) thank you

5 years ago
OpenStudy (anonymous):

You're welcome.

5 years ago