OpenStudy (anonymous):

if f(x)=x^(2)+1 and, g(x)=2x, find [f times g](x)

5 years ago
OpenStudy (anonymous):

I think you mean\[(f^{o}g)(x)\]?This is simply\[f(g(x))\]If\[f(x)=(x)^{2}+1\]and\[g(x)=2x\]just replace every instance of x with 2x.

5 years ago
OpenStudy (anonymous):

yea i think i do mean that.. and why do i do that, just wondering

5 years ago
OpenStudy (anonymous):

\[(f^{o}g)(x)=f(g(x))\]is where you have f as a function of g, and g is a function of x. So in this particular case\[f(g)=(g)^{2}+1\]but\[g(x)=2x\]So replacing g in the first function with its equivalent (2x) gives f(g(x)):\[f(g(x))=(2x)^{2}+1\]Does that make sense?

5 years ago
OpenStudy (anonymous):

yes it does :) thank you

5 years ago
OpenStudy (anonymous):

You're welcome.

5 years ago