Question

1000=(10000)/(5+1245e^(-0.97t)

need help to solve this pretty please?

Answer 1

$$\begin{align*}
1000&=\frac{10000}{5+1245e^{-0.97t}}\\
5+1245e^{-0.97t}&=10\\
1245e^{-0.97t}&=5\\
e^{-0.97t}=\frac{1}{249}\\
-0.97t&=\ln\left[\frac{1}{249}\right]\\
t=\frac{\ln(249)}{0.97}
\end{align*}$$