Question

If a ball is thrown into the air with a velocity of 50 ft/s, its height (in feet) after t seconds is given by y=50t−16t2. Find the velocity when t=8

Answer 1

\[y=50t-16t^2\]
\[y'=50-32t\] put \(t=8\) so find your answer

Answer 2

on the other hand maybe this is a trick question, because it hits the ground before 8 second have elapsed so the real answer is zero, as it is on the ground

Answer 3

thanks a lot.