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Determine the nature of the root : (x – 2a)(x – 2b) = 4ab
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when i solved , i get, x^2-2x(a+b)=0 D = b^2-4ac= 4(a+b)>0 Hence, roots are real.. i just want to confirm my answer
D = b^2-4ac= 4(a+b)^2>0
agree :)
thank u
yw
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