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What is the value of 1 over 2^-2 x^-3 y^5 for x = 2 and y = -4?
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substitute
I don't know how to do this at all..
ok look
you have this 2^-2 x^-3 y^5 now x= 2 and y = -4 2^-2 (2)^-3 (-4)^5 =1/4. 1/8. (-1024) = -1024/32 do it
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