Question

4x^2-5x+1

Answer 1

\[4x^{2}-5x+1=0\]
split the middle term
\[4x ^{2}-4x-x+1=0\]
take common
\[4x(x -1)-1(x-1)=0\]
\[(x-1)(4x1)=0\]

Answer 2

last step is

(x-1) (4x-1)=0

Answer 3

thank you!

Answer 4

welcome ! :)