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Help with dividing algebraic fractions? x^3/x-1 divided by x^2/y-xy
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a/b divided by c/d is a/b times d/c
after writing in this form (multiplication) cancel factors
\[\dfrac{x^3}{(x-1)} \div \dfrac{x^2}{(y-xy)}\]\[\dfrac{x^3}{(x-1)} \times \dfrac{y(x-1)}{x^2}\]
This will help u a lot & i think u can do the remaining work now :)
\[\huge\frac{ x^3 }{ x-1 }\times \frac{ y(x-1) }{ x^2 }\]
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Thank you! (: and now I cancel out the factors...?
yup & yw :)
I got xy? Is this correct?
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