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simplyfy
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\[0.2=\cos(\frac{ \pi t }{ 12 })\]
solve for t
\[\frac{\pi t}{12}=\arccos (0.2)\]
oopss i did not think this way thx
but are you allowed to use calculator \[\pi t/12=\pm \arccos(0.2)+2 \pi k,\forall k\in Z\]
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i got 5.231 but i only got one what about other value
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