Question

When finding the area enclosed by the curves x=4-y^2 and x=y+2, how do you determine which is the right-most or left-most function? I have determined that the integral runs from 0 to 3.

Answer 1

Draw the curves and find the intersection points.

Answer 2

x=-2,1

Answer 3

-2=4-y^2 -> y=sqrt(6)
-2=y+2 -> y=-4
so I think you messed up