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Mathematics 21 Online
OpenStudy (anonymous):

please help! What is the complete factorization of (x^6 - 64)

OpenStudy (perl):

I would start with the lower powers first (x^3)^2 - 8^2 = , which is a difference of squares. (x^3 - 8)( x^3 + 8). now you can factor a sum of cubes and a difference of cubes

OpenStudy (anonymous):

thank you!! @perl so on my hw one of the choices is (x^3 - 8)( x^3 + 8) is that the correct answer? :o

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