show that the sum of a complex number and its conjugate is twice the real part of the number, and the difference is twice the imaginary part of the number.
do u knw what is complex no.?
let me know that first?
(a+bi) - (a-bi) = 2b i
@manishsatywali : yes i know it..
so fr the moment u have been provided that : for a complex no . A+ Bi
what will be it's conjugate ???? tell me asap
@perl : thanks..
@manishsatywali : a-bi
k now according to th equestion there r two conditions first diffrence and sum of complex no. and it's conjugate ......ok
oh i messed up the first one
(a+bi) + ( a-bi) = 2a (a+bi) - (a-bi) = 2b i
frst let's focus on the sum of complex no. and it's conjugate
manish, dont sweat it bro. this is done
where is my medal?
(a+bi) + ( a-bi) = 2a (a+bi) - (a-bi) = 2b i
@perl pls...dn't give direct answer...............i getting whether she everything about the question or not right from base level
@manishsatywali : i agree..
manish, dont sweat it bro.
manish, i got this bro
nw sum (A-Bi ) + (A-Bi).........do it fast ?????????????@meejoy
no thats wrong manish
manish, here (a+bi) + ( a-bi) = 2a (a+bi) - (a-bi) = 2b i
a = Re(z) , b = Im (z) ,
@perl bro pls. w8
@meejoy do the sum
ok sorry :) message me if you have question
@perl and @manishsatywali : this is for studying purpose... but it seems this just gave me a mess. >_<
@meejoy.........pls do the sum
@perl and @manishsatywali : stop the wild talk ..
wild talk?
2A-2Bi
srry @meejoy u gt the wrong answer + Bi and - Bi must cancel
you ask me to get the sum of this right ? (A-Bi ) + (A-Bi) .. how come that Bi must be cancel???
@manishsatywali : are you still here?
@perl : will you pls help me to know and understand the right answer and solution? thanks..
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