Question

Please Help! Best Response!
B = 36°, a = 41, c = 20

b ≈ 27.5, C ≈ 115.5, A ≈ 28.5

b ≈ 45.3, C ≈ 25.5, A ≈ 118.5

b ≈ 45.3, C ≈ 29.5, A ≈ 114.5

b ≈ 27.5, C ≈ 25.5, A ≈ 118.5

Answer 1

did you try this? if yes, where r u stuck?
do you know sine law ?

Answer 2

I do know applying it to problems like this one

Answer 3

ok, let me tell you both the laws which you can use here :
SINE LAW:
\(\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}\)
COS LAW :
\(b^2=a^2+c^2+2ac \cos B\)
do you know whic law/formula you can use first ?

Answer 4

sorry its,
\(b^2=a^2+c^2-2ac \cos B\)

Answer 5

so itd b b^2 = 41^2 + 20^2 - 2(41) cos 36?

Answer 6

you missed 'c' =20
b^2 = 41^2 + 20^2 - 2(41) (20) cos 36
otherwise it was correct,
so you can find 'b' directly from here! can u?

Answer 7

Is it 755?

Answer 8

thats is b^2, so b =.... ?

Answer 9

27.4

Answer 10

so how do i find C?

Answer 11

yes, approx its b=27.5
good :)

Answer 12

now you can use sine law

Answer 13

you know b, sin B and c
so, you can find sin C
\(\dfrac{\sin B}{b}=\dfrac{\sin C}{c}\)

Answer 14

I got 25.5 :)

Answer 15

yes!
now again using sine law, finish it by findind A also.

Answer 16

Okay thank you so much!, you helped me a lot! :)

Answer 17

welcome ^_^