What is log (x+2) - log x = 2 ? Please Answer po . :DD
you need to solve for 'x' right ? use the property that \(\log x-\log y = \log (x/y)\)
yes po .. :D i already try that po ..
so, which step are you stuck ?
po po po po po, po po po pooo! ^_^
@shubhamsrg che! :D haha!
i don't know po. hehe! :DD
if you used that formula, you must be here, log [(x+2)/x ] =2 right ? now since log has base 10, use, \(\log a=b \implies a=10^b\) here a= [(x+2)/x ] ,b =2
yeah .. i get it .. the naswer is 2/99 right??
yes! :) good.
any more doubts ?
none po .. :d thank you po for helping me. GOD bless you always po . :D
welcome ^_^ God bless you too :)
naks! :D thank you again po. :D :D SAYOUNARA! XIE XIE. :D
i know SAYOUNARA means bye :D good bye :)
or am i incorrect ? O.o
:D correct! :D clap! clap! clap! :D very good! :D haha!
thank you thank you :D :)
:D welcome welcome welcome po . :D haha! why are you so good po in math?
because when i was studying maths, i did lots and lots of practice! thats the only secret for learning math....
wow! :D hehe .. :D "MAGAYA NGA!" :D did you know that word po?
no don't know.... but i can always use google translate ;)
ahh .. hehe! it means "i will imitate that po" :D what is your nationality po?
ohh..ok i am INDIAN .
:D wow! :D nice.. okay po. :D hehe.. nice to meet you sir ? what is your real name po by the way?
nice to meet you too innie :) my real name is Hardik :)
:D ahh! hehe .. how did you know again po my nickname? hm .. i didn't get it last time when im asking you that po but i'm replying "YES" even i don't understand po . .hehe! :D
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