Question

In the figure, triangles ABC and BCD are right triangles. AB=6cm and CD= 3 cm.
Also PQ is perpendicular to BC. find the length of PQ.

Answer 1

here PQ/3 = BQ/BC (BPQ and BDC are similar triangles )
also PQ/6= QC/BC (ABC and PQC are similar triangles )

BQ/BC +QC/BC =1
PQ/3 +PQ/6 =1
or PQ(1/3+1/6) =1
or PQ/2 =1
hence PQ=2 cm