Question

(x/x-3)^2-2(x/x-3)-15=0

Answer 1

If you write it in proper math notation:\[\left( \frac{ x }{ x-3 } \right)^2-2\left( \frac{ x }{ x-3 } \right)-15=0\]you see that it looks like a quadratic equation...

So set p=x/(x-3) to get:\[p^2-2p-15=0\]
Solve for p.
Then remember that p=x/(x-3) and solve that for x!

Answer 2

Yeah whenever I do that I get x=5 and x=-3 but I don't know how to go from there

Answer 3

But you get p=5 and p=-3, so you still have to do solve\[\frac{ x }{ x-3 }=5\]and\[\frac{ x }{ x-3 }=-3\]I will get you started with these:\[\frac{ x }{ x-3 }=\frac{ 5 }{ 1 }\]You see two equal fractions. In general this can be dealt with the following way:\[\frac{ a }{ b }=\frac{ c }{ d } \Leftrightarrow ad=bc\]So do the multiplications and then solve for x.

Answer 4

X=9/2 and x= 5/2

Answer 5

Hold on, let me do it myself... ;)

Answer 6

I've found different solutions, I'm afraid...\[x \cdot 1=5 \cdot (x-3) \Leftrightarrow x=5x-15 \Leftrightarrow 4x=15\]so x=15/4.

Maybe you forgot to multiply 5 and -3?

Answer 7

Second one: x*1=-3*(x-3), so x=-3x+9, 4x=9, x=9/4

So I've got 15/4 and 9/4

Answer 8

ok let me see how you did it lol

Answer 9

I just did...!

Answer 10

Do you understand what went wrong?

Answer 11

No, I don't see how you get 5/1

Answer 12

oh wait! I get it nvm!

Answer 13

Welcome!

Answer 14

Thank you so much! I was so lost! lol

Answer 15

Next time, you won't be!