In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 2x – 5, and HE = 5y + 2. Find the values of x and y.

x = 39, y = 14
x = 13, y = 36
x = 14, y = 39
x = 36, y = 13

Question

In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 2x – 5, and HE = 5y + 2. Find the values of x and y. 
 
   x = 39, y = 14 
 x = 13, y = 36 
 x = 14, y = 39 
 x = 36, y = 13

raden · Answer

diagram ?

anonymous · Answer

no

raden · Answer

where is the H ?

whpalmer4 · Answer

I think this is the diagram.

anonymous · Answer

In the middle

whpalmer4 · Answer

So we have two equations in two unknowns, because either side of the diagonal must be equal.

whpalmer4 · Answer

$$x+3 = 3y$$For the DH-HF diagonal
$$2x-5=5y+2$$For the EH-HG diagonal
Solve by elimination or substitution.

anonymous · Answer

x=39,y=14.  x=13,y=36.  x=36,y=13.  x=14,=39. these are my answer choices.

whpalmer4 · Answer

The correct answer is among them.  You could solve the equations, as I suggested, or you could try them all out to see which one works for both equations.

whpalmer4 · Answer

I'd be happy to help you solve them, but you have to put in some effort!