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OpenStudy (anonymous):
Sylvanite is a mineral that contains 28.0\% gold by mass. How much sylvanite would you need to dig up to obtain 87g of gold?
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OpenStudy (jamesj):
Call the amount of sylvanite X. Then the amount of gold, g is \[ g = \frac{28}{100}X \] You know you want \( g = 87 \) grams. Now solve for X.
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