Question

What is the range for y = 0.05x^2 - x + 1 ?

Answer 1

y(x) = ax2 + bx + c,
this is a parabola

if a > 0, the parabola opens upward

if a < 0, the parabola opens downward.



to find the range for your equation, you need to find the minimum value (vertex) of the parabola.
The equation is: x = -b/(2a)

when you have x plug it back into the equation and solve for y

that is your range.