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Precalculus 13 Online
OpenStudy (anonymous):

Simplify 4 sin x cos x csc x

OpenStudy (luigi0210):

it is 4cosx I think. The sinx and cscx would cancel out

OpenStudy (anonymous):

(1/cscx)(1/sinx) =

OpenStudy (anonymous):

can you help on this one

OpenStudy (luigi0210):

well if you multiply it together then it'll be [1/(cscx sinx)]..

OpenStudy (luigi0210):

so it could be 1/1.. I'm honestly not sure, sorry.

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