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The legs of a right triangle measure 5 inches and 7 inches. If theta is the angle between the 5-inch leg and the hypotenuse, sin theta = _____. A. .07 B. .58 C. .71 D. .81
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|dw:1359686819881:dw|
hypotenuse is \(\sqrt{5^2+7^2}=\sqrt{25+49}=\sqrt{74}\) and the sine is \(\frac{7}{\sqrt{74}}\)
7/√74=.813 so D :) thanks!!
yw
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