Question

factor 2x2-8x+8

Answer 1

First, factor out a common factor:
2(x^2 - 4x + 4)
Now look for 2 numbers whose product is 4 and whose sum is -4: -2 and -2
2(x - 2)(x - 2)
2(x - 2)^2

Answer 2

can you help me find the x intercepts i forgot to put that in there but thx :)

Answer 3

To find x-intercepts, you need to solve for y = 0
y = 2x^2 - 8x + 8
Let y = 0
2x^2 -8x + 8 = 0
We already know the factoring is:
2(x - 2)^2 = 0
x - 2 = 0 or x - 2 = 0
x = 2 or x = 2
The x-intercept is x = 2

Answer 4

thx :)

Answer 5

yw