Question

solve f(x)=0 for x, f(x)=3x^2- 12.

Answer 1

f(x)=3x^2- 12

0 = 3x^2 - 12
+12 +12

12 = 3x^2
/3 /3

4 = x^2

\[\sqrt{4}= \sqrt{x^2}\]\[2=x\]

Does that make sense? :o)

Answer 2

it says i need 2 answers ):

Answer 3

Well, it'd be 2 and -2

http://www.wolframalpha.com/input/?i=f%280%29%3D3x%5E2-+12

Can you see the graph?