Solving the following equation will require you to use the quadratic formula. Solve the equation for theta between 0 degrees and 360 degrees and round your answers to the nearest tenth of a degree.

3sin^2θ-2cosθ-1=0

a. 56.1 degrees, 303.9 degrees
b. 56.7 degrees, 303.3 degrees
c. 57.5 degrees, 302.5 degrees
d. 57.1 degrees, 302.9 degrees
e. 56.9 degrees, 303.1 degrees

Question

Solving the following equation will require you to use the quadratic formula. Solve the equation for theta between 0 degrees and 360 degrees ￼ and  round your answers to the nearest tenth of a degree.

3sin^2θ-2cosθ-1=0

a. 56.1 degrees, 303.9 degrees￼￼￼￼￼
b. 56.7 degrees, 303.3 degrees
c. 57.5 degrees, 302.5 degrees
d. 57.1 degrees, 302.9 degrees
e. 56.9 degrees, 303.1 degrees

anonymous · Answer

Oh, I think I got it. 3sin^2(x)-2cos(x)-1=0 becomes -3cos^2(x)-2cos(x)+2=0

anonymous · Answer

and then the quadratic formula applied from there. a=-3 b=-2 c=2

radar · Answer

Using the trig identity$$\cos ^{2} \theta +\sin ^{2} \theta=1$$\ looks like a good approach