Question

Evaluate for x = 2 and y = 3: (x^2y^-3)/(x^-1y)

Answer 1

plug in the values given

Answer 2

How does that work?

Answer 3

x=2 y=3 (x^2y^-3)/(x^-1y) plug 2 in for x so (2^2y^-3)/(2^-1y) then plug 3 in for y so (2^2*3^-3)/(2^-1*3)

Answer 4

you can solve from there

Answer 5

x^2 if x= 2 then 4