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Mathematics 6 Online
OpenStudy (anonymous):

Use the Intermediate Value Theorem to verify that f(x) has a zero in the given interval. Then use the method of bisections to find an interval of length 1/32 that contains the zero.f(x) = x^2 - 7, [2,3]

OpenStudy (anonymous):

1st part, replace x =2 you have f(x) = -3 (negative value) replace x =3 you have f(x) = 2( positive value). of course, the function is continuous, and go from negative value to positive value, it must cut the x axis. and at that point, f(x) =0

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