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Is (x+8) a factor of x^2+16x+64? I got (x+8). Please check my work. Thank you.
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It should help.
it didn't but thank you.
Darn, sorry man.
Did you try multiplying out the factors you found? The product of all the factors should give you the original polynomial.
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\[(x+8)(x+8)\]\[x^{2} + 8x +8x + 64\]\[x^{2} + 16x +64\]
I did do that but I just wanted to be sure. Thank you.
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