Question

what is the answer to this system of equations I tried elimination and substitution but it didn't work. Need help.

2x-y+3z=8
x-6y-z=0
-6x+3y-9z=24

Answer 1

Show the work that you did using the method you feel more strongly in to see where you may have messed up or where you get stuck.

Answer 2

\[2x-y+3z=8[1]\]
\[x-6y-z=0[2]\]
\[-6x+3y-9z=24[3]\]
\[[2]\]
\[x=6y+z\]
\[[1]\]
\[2(6y+z)-y+3z=8\]
\[12y+6z-y+3z=8\]
\[11y+9z=8[4]\]
\[[3]\]
\[-6(6y+z)+3y-9z=24\]
\[-36y-6z+3y-9z=24\]
\[-33y-15z=24[5]\]
\[[4]\times 3\]
\[3(11y+9z)=3(8)\]
\[33y+27z=24[6]\]
\[[5]+[6]\]
\[(-33y-15z)+(33y+27z)=(24)+(24)\]
\[-15z+27z=48\]
\[12z=48\]
\[z=?\]

Answer 3

The common intersection of the system is not a unique point.