there are 3 caskets.1st one contains 2 gold coins, 2nd one contains 1 gold and 1 silver coins and 3rd one contains 2 silver coins.I choose one caskets at random and draw a coin.If the coin is gold,probability that the 2nd coin in the casket is gold can be written as a/b where a,b are co prime positive numbers.Then a+b=?

Question

there are 3 caskets.1st one contains 2 gold coins, 2nd one contains 1 gold and 1 silver coins and 3rd one contains 2 silver coins.I choose one caskets at random and draw a coin.If the coin is gold,probability that the 2nd  coin in the casket is gold can be written as a/b where a,b are co prime positive numbers.Then a+b=?

shubhamsrg · Answer

BRILLIANT.ORG !

shubhamsrg · Answer

:P

shubhamsrg · Answer

P(choosing 2nd casket) =1/3
P(gold coin from 2nd casket) = 1/2
P(gold from 1st) = 1
P(gold from 3rd) = 0

So required probab = (1/3)*(1/2) / [ (1/3)*1 + (1/3)*(1/2) + (1/3)*0 ]

Just simplify this

anonymous · Answer

Can someone help me over modulo arithmatics