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Differential Equations
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can anyone plz solve y'' - y = 8*e^-3*x ???? plz it is urgent ......
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e^(-3x) or (e^-3)*x Am assuming the former one ?
the 1st one. and also the paricular solution is e^(-3*x)..
y= C e^(-3x) works right ? y' = -3C( e^-3x) y'' = 9C(e^-3x) => 9C(e^(-3x)) - C(e^-3x) = 8(e^(-3x)) C=1 so y=e^(-3x) is a solution.
what about the value of C ??????? can it be any cosnt or somthing else ?
We just solved it, C=1
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infact, Ae^x + Ce^(-3x) can also be a soltuion.
where C=1 and A can be anything
thnak u....
I am pretty sure there might be more solutions to it. Nevermind
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