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Find the slope and y intercept of the line that passes through (2,8)(10,20)
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Use the equation y=mx+c The slope of the line through points (x1,y1) and (x2,y2) is given by : \(\huge m=\frac{y_1-y_2}{x_1-x_2}\) now,just put the values and first find m.
Ok so I got 1.5 for m
correct! m= 1.5 or 3/2 now, you have y= 1.5x+c and a point on it , say lets take 2,8 so plug in x=2,y=8 in y=1.5x+c and find c= ... which is your y-intercept.
c=2.6
So how do I get my y intercept
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So my slope is 1.5 and y intercept 2.6
plug in x=2,y=8 in y=1.5x+c 8= 1.5(2)+c ----> c= 8-3=5 c=5= y-intercept.
ok so slope 1.5 and y intercept is 5
yes, correct.
thank you
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welcome ^_^
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