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is the sin120 degrees -1/2?
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\[\sin 120=\sin (180-60)=\sin 60=\sqrt {3}\]
/2
just remember that on the unit circle, sin is your y-coordinate cos is your x-coordinate.
Still on the top-half of the unit circle, so sin is positive there...
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what is it looking for
it's basically a yes/no question...
it just said find each trigonometric ratio and gave me sin120.
oh i see, so since sin is the y axis, it would be sqrrt3/2
correct... sin is the y-coordinate, not the y axis...
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