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when a resistor is connected to an independent source,the current flow in it depends on whether the power rating or resistance?
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resistance. Power comes later.
\[V=IR=>I=\frac{V}{R}\]Looking at those equations (as @Shadowys said) you should see that current is inversely related to resistance. Power should be considered more of a result of the current and voltage: \[P=IV\]
The power rating is how much heat the resistor can dissipate without melting, burning or otherwise wrecking itself.
That's true also but I don't think that's what the question is asking
thanks
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