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For the limit lim x → 3 (x^3 − 3x + 8) = 26 ε = 0.2 δ = ε = 0.1 δ =
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so we have |x^3 - 3x + 8 - 26| < 0.2 when |x - 3| < δ Can someone show me how to do this kind of problem? At least for the first value of the epsilon?
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