Question

Find the smallest value of n so that 180n is a cube number
(show working out please)

Answer 1

n = 150

Answer 2

180n = 3^2 * 2^2 * 5 * n
so n must be equal to 3 * 2 * 5 ^2

Answer 3

so do we just write the ans as 150 or do we need to times with it with 180 (180x150) or 150 is the ans? thanks for replying as i have an exam tmr

Answer 4

yes the answer is 150.

Answer 5

if you dont mind can you please help me with this question ( Find the smallest value of n such that 1800n is a perfect cube) srry as i really suck in math :3

Answer 6

1800n = 3^2 * 2^3 * 5^2 * n
smallest value for n = 3 * 5 = 15

Answer 7

Thank you very much!:)

Answer 8

good luck with your exam :)