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OpenStudy (anonymous):
prove sec^2θ/over/sec^2θ-1=csc^2
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OpenStudy (anonymous):
sec²θ/sec²θ-1 = csc²θ ， （1/cos²θ） * （cos²θ/sin²θ） = csc²θ ， （1/sin²θ）=csc²θ ， csc²θ=csc²θ √
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