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Precalculus 18 Online
OpenStudy (anonymous):

prove sec^2θ/over/sec^2θ-1=csc^2

OpenStudy (anonymous):

sec²θ/sec²θ-1 = csc²θ , (1/cos²θ) * (cos²θ/sin²θ) = csc²θ , (1/sin²θ)=csc²θ , csc²θ=csc²θ √

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